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5x^2-18=-7x
We move all terms to the left:
5x^2-18-(-7x)=0
We get rid of parentheses
5x^2+7x-18=0
a = 5; b = 7; c = -18;
Δ = b2-4ac
Δ = 72-4·5·(-18)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{409}}{2*5}=\frac{-7-\sqrt{409}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{409}}{2*5}=\frac{-7+\sqrt{409}}{10} $
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